Integrand size = 14, antiderivative size = 24 \[ \int \sin ^2(x) (a \cos (x)+b \sin (x)) \, dx=-b \cos (x)+\frac {1}{3} b \cos ^3(x)+\frac {1}{3} a \sin ^3(x) \]
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Time = 0.06 (sec) , antiderivative size = 24, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.286, Rules used = {3168, 2644, 30, 2713} \[ \int \sin ^2(x) (a \cos (x)+b \sin (x)) \, dx=\frac {1}{3} a \sin ^3(x)+\frac {1}{3} b \cos ^3(x)-b \cos (x) \]
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Rule 30
Rule 2644
Rule 2713
Rule 3168
Rubi steps \begin{align*} \text {integral}& = \int \left (a \cos (x) \sin ^2(x)+b \sin ^3(x)\right ) \, dx \\ & = a \int \cos (x) \sin ^2(x) \, dx+b \int \sin ^3(x) \, dx \\ & = a \text {Subst}\left (\int x^2 \, dx,x,\sin (x)\right )-b \text {Subst}\left (\int \left (1-x^2\right ) \, dx,x,\cos (x)\right ) \\ & = -b \cos (x)+\frac {1}{3} b \cos ^3(x)+\frac {1}{3} a \sin ^3(x) \\ \end{align*}
Time = 0.04 (sec) , antiderivative size = 26, normalized size of antiderivative = 1.08 \[ \int \sin ^2(x) (a \cos (x)+b \sin (x)) \, dx=-\frac {3}{4} b \cos (x)+\frac {1}{12} b \cos (3 x)+\frac {1}{3} a \sin ^3(x) \]
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Time = 0.43 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.83
method | result | size |
default | \(-\frac {b \left (2+\sin \left (x \right )^{2}\right ) \cos \left (x \right )}{3}+\frac {a \sin \left (x \right )^{3}}{3}\) | \(20\) |
parts | \(-\frac {b \left (2+\sin \left (x \right )^{2}\right ) \cos \left (x \right )}{3}+\frac {a \sin \left (x \right )^{3}}{3}\) | \(20\) |
risch | \(-\frac {3 b \cos \left (x \right )}{4}+\frac {a \sin \left (x \right )}{4}+\frac {b \cos \left (3 x \right )}{12}-\frac {a \sin \left (3 x \right )}{12}\) | \(26\) |
norman | \(\frac {-4 \tan \left (\frac {x}{2}\right )^{2} b +\frac {8 \tan \left (\frac {x}{2}\right )^{3} a}{3}-\frac {4 b}{3}}{\left (1+\tan \left (\frac {x}{2}\right )^{2}\right )^{3}}\) | \(34\) |
parallelrisch | \(\frac {-4 \tan \left (\frac {x}{2}\right )^{2} b +\frac {8 \tan \left (\frac {x}{2}\right )^{3} a}{3}-\frac {4 b}{3}}{\left (1+\tan \left (\frac {x}{2}\right )^{2}\right )^{3}}\) | \(35\) |
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Time = 0.26 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.12 \[ \int \sin ^2(x) (a \cos (x)+b \sin (x)) \, dx=\frac {1}{3} \, b \cos \left (x\right )^{3} - b \cos \left (x\right ) - \frac {1}{3} \, {\left (a \cos \left (x\right )^{2} - a\right )} \sin \left (x\right ) \]
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Time = 0.10 (sec) , antiderivative size = 27, normalized size of antiderivative = 1.12 \[ \int \sin ^2(x) (a \cos (x)+b \sin (x)) \, dx=\frac {a \sin ^{3}{\left (x \right )}}{3} - b \sin ^{2}{\left (x \right )} \cos {\left (x \right )} - \frac {2 b \cos ^{3}{\left (x \right )}}{3} \]
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none
Time = 0.21 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.83 \[ \int \sin ^2(x) (a \cos (x)+b \sin (x)) \, dx=\frac {1}{3} \, a \sin \left (x\right )^{3} + \frac {1}{3} \, {\left (\cos \left (x\right )^{3} - 3 \, \cos \left (x\right )\right )} b \]
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none
Time = 0.27 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.04 \[ \int \sin ^2(x) (a \cos (x)+b \sin (x)) \, dx=\frac {1}{12} \, b \cos \left (3 \, x\right ) - \frac {3}{4} \, b \cos \left (x\right ) - \frac {1}{12} \, a \sin \left (3 \, x\right ) + \frac {1}{4} \, a \sin \left (x\right ) \]
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Time = 22.55 (sec) , antiderivative size = 32, normalized size of antiderivative = 1.33 \[ \int \sin ^2(x) (a \cos (x)+b \sin (x)) \, dx=-\frac {4\,\left (-2\,a\,{\mathrm {tan}\left (\frac {x}{2}\right )}^3+3\,b\,{\mathrm {tan}\left (\frac {x}{2}\right )}^2+b\right )}{3\,{\left ({\mathrm {tan}\left (\frac {x}{2}\right )}^2+1\right )}^3} \]
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